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简单做个备份

VTI介质ADCIGs中剩余曲率根据角度的变化可以进一步分析得出反演策略，根据相速度公式求解的深度残差关于Thomsen参数的偏导数：

#include
   
    #include
    
     #include
     
      float deltaz(float v, float e, float d, float theta){    float vp=2000;    float beta=0.0;    float t=1;    theta *= 3.1415926/180.0;        return (v-vp)*t/(2.0*cos(theta)*cos(beta))            *sqrt(0.5 + e*sin(theta-beta)*sin(theta-beta)                    + 0.5*sqrt( pow(1+2*e*sin(theta-beta)*sin(theta-beta),2.0 )                                - 2*(e-d)*sin(2*theta-2*beta)*sin(2*theta-2*beta))  );}int main(int argc, char **argv){    float diff = 0.1;    float theta, dzv, dze, dzd;    int i;        FILE *fp1 = fopen("dz.txt","w");        for(i=0;i<90;i++){                theta = i*1.0;        dzv = deltaz(1800-diff, 0.5, 0.3, theta) - deltaz(1800, 0.5, 0.3, theta);        dze = deltaz(1800, 0.5+diff, 0.3, theta) - deltaz(1800, 0.5, 0.3, theta);        dzd = deltaz(1800, 0.5, 0.3+diff, theta) - deltaz(1800, 0.5, 0.3, theta);            printf("%f, %f, %f\n",dzv,dze,dzd);        fprintf(fp1,"%f     %f     %f\n",dzv,dze,dzd);    }}
     
    
   

得出关系曲线：